2y^2(4y^3-19y^2-5)=0

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Solution for 2y^2(4y^3-19y^2-5)=0 equation:


Simplifying
2y2(4y3 + -19y2 + -5) = 0

Reorder the terms:
2y2(-5 + -19y2 + 4y3) = 0
(-5 * 2y2 + -19y2 * 2y2 + 4y3 * 2y2) = 0
(-10y2 + -38y4 + 8y5) = 0

Solving
-10y2 + -38y4 + 8y5 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2y2'.
2y2(-5 + -19y2 + 4y3) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'y2' equal to zero and attempt to solve: Simplifying y2 = 0 Solving y2 = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y2 = 0 Take the square root of each side: y = {0}

Subproblem 2

Set the factor '(-5 + -19y2 + 4y3)' equal to zero and attempt to solve: Simplifying -5 + -19y2 + 4y3 = 0 Solving -5 + -19y2 + 4y3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

y = {0}

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